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Oracle 1Z0-804 Exam Sample Questions

Question: 1

Given:

class A {

int a = 5;

String doA() { return “a1 “; }

protected static String doA2 () { return “a2 “; }

}

class B extends A {

int a = 7;

String doA() { return “b1 “; }

public static String doA2() { return “b2 “; }

void go() {

A myA = new B();

System.out.print(myA .doA() + myA .doA2() + myA .a);

}

public static void main (String[] args) {

new B().go();

}

}

Which three values will appear in the output?

  1. 5
  2. 7
  3. a1
  4. a2
  5. b1
  • b2

  • Answer: A, D, E

    Explanation:

    Static method of base class is invoked >>

    A myA = new B();

    System.out.print(myA.doA() + myA.doA2() + myA.a);

    class B String doA() { return “b1 “; }

    class A protected static String doA2 () { return “a2 “; }

    class B int a = 7;

    Question: 3

    Given:

    interface Rideable {

    String ride() ;

    }

    class Horse implements Rideable {

    String ride() { return “cantering “; }

    }

    class Icelandic extends Horse {

    String ride() { return “tolting “; }

    }

    public class Test1 {

    public static void main(String[] args) {

    Rideable r1 = new Icelandic();

    Rideable r2 = new Horse();

    Horse h1 = new Icelandic();

    System.out.println(r1.ride() + r2.ride() + h1.ride());

    }

    }

    What is the result?

    1. tolting cantering tolting
    2. cantering cantering cantering
    3. compilation fails
    4. an exception is thrown at runtime


    Answer: C

    Explanation:

    Compiler says: Cannot reduce the visibility of the inherited method from Rideable. müssen PUBLIC sein

    public String ride() { return “cantering “; }

    public String ride() { return “tolting “; }

    if this is given then the result would be:

    A : tolting cantering tolting

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    Question: 5

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    – Type x is a template for other types in the application.

    – Type x implements dostuff ().

    – Type x declares, but does NOT implement doit().

    – Type y declares doOther() .

    Which three are true?

    1. Type y must be an interface.
    2. Type x must be an abstract class.
    3. Type y must be an abstract class.
    4. Type x could implement or extend from Type y.
    5. Type x could be an abstract class or an interface.
  • Type y could be an abstract class or an interface.

  • Answer: B, D, F

    Explanation:

    Unlike interfaces, abstract classes can contain fields that are not static and final, and they can contain implemented methods. Such abstract classes are similar to interfaces, except that they provide a partial implementation, leaving it to subclasses to complete the implementation. If an abstract class contains only abstract method declarations, it should be declared as an interface instead.

    Note:

    An interface in the Java programming language is an abstract type that is used to specify an interface (in the generic sense of the term) that classes must implement. Interfaces are declared using the interface keyword, and may only contain method signature and constant declarations (variable declarations that are declared to be both static and final). An interface may never contain method definitions.

    Note 2: an abstract class is a class that is declared abstract–it may or may not include abstract methods. Abstract classes cannot be instantiated, but they can be subclassed. An abstract method is a method that is declared without an implementation (without braces, and followed by a semicolon)

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    Question: 5

    Given these facts about Java types in an application:

    – Type x is a template for other types in the application.

    – Type x implements dostuff ().

    – Type x declares, but does NOT implement doit().

    – Type y declares doOther() .

    Which three are true?

    1. Type y must be an interface.
    2. Type x must be an abstract class.
    3. Type y must be an abstract class.
    4. Type x could implement or extend from Type y.
    5. Type x could be an abstract class or an interface.
  • Type y could be an abstract class or an interface.

  • Answer: B, D, F

    Explanation:

    Unlike interfaces, abstract classes can contain fields that are not static and final, and they can contain implemented methods. Such abstract classes are similar to interfaces, except that they provide a partial implementation, leaving it to subclasses to complete the implementation. If an abstract class contains only abstract method declarations, it should be declared as an interface instead.

    Note:

    An interface in the Java programming language is an abstract type that is used to specify an interface (in the generic sense of the term) that classes must implement. Interfaces are declared using the interface keyword, and may only contain method signature and constant declarations (variable declarations that are declared to be both static and final). An interface may never contain method definitions.

    Note 2: an abstract class is a class that is declared abstract–it may or may not include abstract methods. Abstract classes cannot be instantiated, but they can be subclassed. An abstract method is a method that is declared without an implementation (without braces, and followed by a semicolon)

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    Question: 1

    Given:

    class A {

    int a = 5;

    String doA() { return “a1 “; }

    protected static String doA2 () { return “a2 “; }

    }

    class B extends A {

    int a = 7;

    String doA() { return “b1 “; }

    public static String doA2() { return “b2 “; }

    void go() {

    A myA = new B();

    System.out.print(myA .doA() + myA .doA2() + myA .a);

    }

    public static void main (String[] args) {

    new B().go();

    }

    }

    Which three values will appear in the output?

    1. 5
    2. 7
    3. a1
    4. a2
    5. b1
  • b2

  • Answer: A, D, E

    Explanation:

    Static method of base class is invoked >>

    A myA = new B();

    System.out.print(myA.doA() + myA.doA2() + myA.a);

    class B String doA() { return “b1 “; }

    class A protected static String doA2 () { return “a2 “; }

    class B int a = 7;

    Question: 3

    Given:

    interface Rideable {

    String ride() ;

    }

    class Horse implements Rideable {

    String ride() { return “cantering “; }

    }

    class Icelandic extends Horse {

    String ride() { return “tolting “; }

    }

    public class Test1 {

    public static void main(String[] args) {

    Rideable r1 = new Icelandic();

    Rideable r2 = new Horse();

    Horse h1 = new Icelandic();

    System.out.println(r1.ride() + r2.ride() + h1.ride());

    }

    }

    What is the result?

    1. tolting cantering tolting
    2. cantering cantering cantering
    3. compilation fails
    4. an exception is thrown at runtime


    Answer: C

    Explanation:

    Compiler says: Cannot reduce the visibility of the inherited method from Rideable. müssen PUBLIC sein

    public String ride() { return “cantering “; }

    public String ride() { return “tolting “; }

    if this is given then the result would be:

    A : tolting cantering tolting